Find dy/dx at the point (-3, 1) for the equation x = y^3-9x^2+5.
rearranging things a bit, we have
y^3 = 9x^2+x-5
3y^2 y' = 18x+1
y' = (18x+1)/(3y^2)
at (-3,1) that means
y' = -53/3
However, (-3,1) is not on the curve. Typo??
y^3 = 9x^2+x-5
3y^2 y' = 18x+1
y' = (18x+1)/(3y^2)
at (-3,1) that means
y' = -53/3
However, (-3,1) is not on the curve. Typo??