A uniform ladder of length 20.0m and weight 750 N is propped up against a smooth vertical wall with its lower end on a rough horizontal surface. The coefficient of friction between the ladder and this horizontal surface is 0.40.

(a) Draw a diagram for the ladder showing all the forces acting on the ladder.

(b) Work out and add the numerical values of each force clearly showing your justification in each case.

(c) Hence, calculate a value for the angle between the ladder and the wall if the ladder just remains in stable equilibrium.

I have done a but can't work out b and c!!!!!

A uniform ladder of length 20.0m and weight 750 N is propped up against a smooth vertical wall with its lower end on a rough horizontal surface. The coefficient of friction between the ladder and this horizontal surface is 0.40.

(b) Work out and add the numerical values of each force clearly showing your justification in each case.

(c) Hence, calculate a value for the angle between the ladder and the wall if the ladder just remains in stable equilibrium.

To work out the numerical values of each force acting on the ladder and calculate the angle between the ladder and the wall, we need to analyze the forces involved. Let's go step by step:

(a) Diagram:

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Wall

This diagram shows the ladder leaning against the wall. The forces acting on the ladder are:

1. Weight (W): downward force acting at the center of mass of the ladder, which we know is 750 N.

2. Normal force (N): upward force exerted by the horizontal surface on the ladder. It acts perpendicularly to the surface.

3. Frictional force (f): force opposing the motion along the horizontal surface, acting parallel to the surface.

4. Contact force (C): force of contact between the ladder and the wall. It acts perpendicular to the surface of the wall.

5. Tension force (T): force in the ladder due to its own weight and the reaction forces from the wall and the horizontal surface.

(b) Numerical values:

Let's calculate the magnitude of each force:

1. Weight (W): Given as 750 N.

2. Normal force (N): This can be calculated using Newton's second law, which states that the sum of all forces in the vertical direction is equal to the product of mass and acceleration. In this case, the acceleration in the vertical direction is zero since the ladder is in equilibrium. Therefore, the normal force is equal to the weight force, which is 750 N.

3. Frictional force (f): The frictional force can be calculated using the equation f = μN, where μ is the coefficient of friction and N is the normal force. Given that the coefficient of friction is 0.40 and the normal force is 750 N, we can calculate the frictional force as f = 0.40 × 750 N = 300 N.

4. Contact force (C): The contact force is equal in magnitude and opposite in direction to the force exerted by the wall on the ladder. Since the ladder is in equilibrium, the contact force and the force exerted by the wall balance each other. Hence, the contact force is also 750 N.

(c) Angle calculation:

To calculate the angle between the ladder and the wall, we can use trigonometry.

Let θ be the angle between the ladder and the wall.

Using the concept of torque equilibrium, the torque due to the weight of the ladder must be balanced by the torque due to the frictional force and the contact force.

The torque due to the weight of the ladder is given by: τ_weight = W × d, where d is the distance of the ladder's center of mass from its lower end.

The torque due to the frictional force is given by: τ_friction = f × L, where L is the length of the ladder.

The torque due to the contact force is given by: τ_contact = C × L × sin(θ), as the contact force acts perpendicular to the ladder and creates a moment arm equal to L × sin(θ).

For stable equilibrium, the torques must cancel out:

τ_weight = τ_friction + τ_contact

Substituting the values:

W × d = f × L + C × L × sin(θ)

Now, let's substitute the known values into the equation:

750 N × (20.0m/2) = 300 N × 20.0m + 750 N × 20.0m × sin(θ)

Solving this equation will give you the angle θ between the ladder and the wall when the ladder is in stable equilibrium.