Susie wants to have at least a 90 average for the year in her Algebra class. Her current test scores are 85, 100, 86, and 97. What does she need to score on her fifth test to have at least a 90 average?
She has a total of 368 points now. She needs at least 450 points for a 90 average.
How many more points does she need?
To find out what Susie needs to score on her fifth test to have at least a 90 average, we need to determine the average of her current test scores and then calculate the score she needs on the fifth test.
First, let's calculate the average of her current test scores:
(85 + 100 + 86 + 97) / 4 = 368 / 4 = 92
Susie's current average is 92.
Next, we need to determine the score she needs on the fifth test to have at least a 90 average for the year.
Let's assume Susie has taken n tests, and her average score is A. To have at least a 90 average, the sum of her test scores should be n * 90.
So far, Susie has taken four tests, and the sum of her scores is 92 * 4 = 368.
To find the score she needs on the fifth test, let's denote it as x.
The sum of her test scores after taking the fifth test would be (368 + x).
To have at least a 90 average for five tests, the sum of her scores should be 5 * 90 = 450.
Therefore, we can set up an equation to solve for x:
(368 + x) / 5 = 90
Multiply both sides of the equation by 5:
368 + x = 450
Subtract 368 from both sides of the equation:
x = 450 - 368
x = 82
So Susie needs to score at least 82 on her fifth test to have at least a 90 average for the year.