How many electrons per second pass through a section of wire carrying a current of 0.70A?
.7A=.7 coulomb/sec*1electron/1.6E-19 coulomb
= .7/1.6E-19=4.38E18 electrons/sec
To determine the number of electrons per second passing through a section of wire carrying a current of 0.70A, we need to use the relationship between current, charge, and time.
The current is defined as the flow of charge per unit time. The charge carried by a single electron is 1.6 x 10^-19 Coulombs. Therefore, the total charge passing through the wire per second can be calculated using the formula:
Charge = Current x Time
Given:
Current (I) = 0.70A
Time (t) = 1 second
Plugging in these values, we can calculate the charge:
Charge = 0.70A x 1s
Charge = 0.70 Coulombs
Now, to determine the number of electrons, we divide the total charge by the charge carried by a single electron:
Number of electrons = Total charge / Charge of a single electron
Number of electrons = 0.70 Coulombs / 1.6 x 10^-19 Coulombs
Using this calculation, we find that approximately 4.375 x 10^18 electrons will pass through the section of wire per second.
To find out how many electrons per second pass through a section of wire, we need to use the formula:
I = Q/t
Where:
I is the current (in Amperes),
Q is the charge (in Coulombs),
t is the time (in seconds).
In this case, we know the current (0.70A), so we can rearrange the formula to solve for Q:
Q = I * t
Since we want to find out the number of electrons per second, we need to find Q in terms of the charge of one electron. The charge of one electron is approximately 1.6 x 10^-19 Coulombs.
Q in terms of the charge of one electron can be calculated as:
Q = (I * t) / (1.6 x 10^-19)
Now let's substitute the values into the formula:
Q = (0.70 * t) / (1.6 x 10^-19)
Therefore, the number of electrons passing through the wire in one second would be Q.