A visually intriguing mathematical query translated into imagery. In the center, visualize an enigma represented by an archaic, golden, antique numeral plate with hollow numbers ranging from 80 to 90. Now, utilize an ethereal hand from the left side of the image, indicating the motion of subtracting one from the number 85. On the other side, present another apparitional hand adding 2, pointing to the number 88. Surround the scene with abstract shapes and colours hinting at mathematical concepts, like grids, calculations or figures.

I am a number between 80 and 90 if you remove one from me I become a multiple of 5. If you add 2 to me I become a multiple of 8 who am I

The only multiple of 5 between 80 and 90 is 85.

Adding one to 85 would be 86.

86 + 2 = 88 which is a multiple of 8.

So, 86 is the answer.

the only one of 5 is 80 between 90 is 85.

1+85=86+2=88
8x11=88😀
answer:
86

Well, well, well, aren't you a mysterious number! Let me put on my detective hat and try to crack this puzzling riddle.

If you're a number between 80 and 90 and by removing one you become a multiple of 5, then you must be 86! Because if we take away one, we get 85, which is indeed a multiple of 5.

But wait, the plot thickens! If we add 2 to you, you become a multiple of 8. So, 86 + 2 equals...88! And what do you know, 88 is a multiple of 8!

So, my friend, you are the enigmatic number 86! Keep up the math tricks, and maybe you'll join a circus where numbers can perform death-defying calculations!

Let's break down the information step-by-step:

Step 1: Start with a number between 80 and 90.
Let's call this number "x".

Step 2: If you remove one from this number, it becomes a multiple of 5.
So, x - 1 is divisible by 5.

Step 3: If you add 2 to this number, it becomes a multiple of 8.
So, x + 2 is divisible by 8.

From the given information, we can deduce that the number "x" must satisfy both conditions, which means it must be a common multiple of 5 and 8.

The least common multiple of 5 and 8 is 40.

To find the number "x", we need to find a number that is 40 more than a multiple of 5. This can be found by adding multiples of 40 to 40.

The numbers that satisfy this condition are: 40, 80, 120, 160, and so on.

However, we are given that the number is between 80 and 90. From the list of numbers, the only number between 80 and 90 is 80.

Therefore, the number is 80.

To solve this problem, let's use algebra.

Let's represent the unknown number as "x".

According to the information provided, the number "x" is between 80 and 90. Therefore, we can write the inequality: 80 < x < 90.

Now, let's examine the given conditions.

Condition 1: If you remove one from the number "x", it becomes a multiple of 5.
This gives us the equation: (x - 1) is divisible by 5, or (x - 1) = 5k, where "k" is an integer.

Condition 2: If you add 2 to the number "x", it becomes a multiple of 8.
This gives us the equation: (x + 2) is divisible by 8, or (x + 2) = 8k, where "k" is an integer.

Now, let's solve these equations:

For the first equation, (x - 1) = 5k, we can simplify it to x = 5k + 1.

For the second equation, (x + 2) = 8k, we can simplify it to x = 8k - 2.

Since we are looking for a number between 80 and 90, we can substitute the values into the inequalities:

80 < x < 90

80 < 5k + 1 < 90 (using the first equation)

80 < 5k + 1 implies that 79 < 5k, or k > 15.8 (rounded up)

The smallest value for k is 16.

We substitute this into the second equation:

x = 8k - 2
x = 8(16) - 2
x = 128 - 2
x = 126

Therefore, the number you are is 126.