A boxer punches a sheet of paper in midair, bringing it from rest to a speed of 25m/s^2 in 0.05 secind. The mass of the paper is 0.003 kg. Show the force of the punch on the paper is only 1.5 N.
You can solve this with
f=ma
To find the force of the punch on the paper, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this can be represented as F = m * a.
Given:
Mass of the paper (m) = 0.003 kg
Acceleration (a) = 25 m/s^2
Using the formula F = m * a, we can calculate the force:
F = 0.003 kg * 25 m/s^2
F = 0.075 N
Hence, the force of the punch on the paper is 0.075 N, not 1.5 N as stated.
It is important to note that the provided value for the force of the punch (1.5 N) may not be accurate or could be derived from additional information. The given mass and acceleration values indicate a force of only 0.075 N.