You toss a ball from your window 8m above the groun. When the ball leaves your hand, ut is moving at 10m/s at an angle of 20 degree below the horizontal. How far horizontally from your window will the ball hit the ground? Ignore air resistance. Plz answer it fast . It's my humble request.
Vo = 10m/s[20o] S. of E.
Xo = 10*Cos20 = 9.4 m/s.
h = 0.5g*Tf^2 = 8 m.
4.9Tf^2 = 8, Tf = 1.28 s. - Fall time.
Dx = Xo*Tf = 9.4m/s * 1.28s = 12 m.
Mery assignment MN ye question h plz koi solve kr do
Vix=Vicos20°=
Viy=Visin20°
8=Viyt + 1/2gt^2
t=-viy/4g
X=Vix t + 1/2 a t^2. |a=0|
X=Vix t
Vix=Vicos20°=
Viy=Visin20°
8= 1/2gt^2
t^2=16g
X=Vix t + 1/2 a t^2. |a=0|
X=Vix t
To find how far horizontally the ball will hit the ground, we can break down the initial velocity into its horizontal and vertical components.
First, let's find the initial vertical velocity component (Vy):
Given that the ball is thrown at an angle of 20 degrees below the horizontal and the initial velocity (V) is 10 m/s, we can use trigonometry to find Vy:
Vy = V * sin(θ)
Vy = 10 * sin(20)
Vy ≈ 3.42 m/s (rounded to two decimal places)
Next, let's find the time it takes for the ball to reach the ground:
We can use the equation of motion to find the time (t) when the ball hits the ground:
y = y0 + Vy * t + (1/2) * g * t^2
Since the ball starts at a vertical height (y0) of 8 m and the final vertical position (y) is 0 (as it hits the ground), we have:
0 = 8 + 3.42 * t + (1/2) * 9.8 * t^2
Simplifying the equation and rearranging:
4.9 * t^2 + 3.42 * t - 8 = 0
Solving this quadratic equation will give us the time it takes for the ball to hit the ground:
Using the quadratic formula:
t = (-b ± √(b^2 - 4ac)) / 2a
where a = 4.9, b = 3.42, and c = -8
Using the quadratic formula, we find two possible values for t:
t ≈ 1.17 seconds (rounded to two decimal places) or t ≈ -1.75 seconds
Since time cannot be negative, we can discard the negative value, so the ball takes approximately 1.17 seconds to hit the ground.
Finally, we can calculate the horizontal distance (dx) using the horizontal velocity component (Vx) and the time (t):
The horizontal displacement (dx) is given by:
dx = Vx * t
Since there is no acceleration in the horizontal direction, the horizontal velocity (Vx) is constant.
Vx = V * cos(θ)
Vx = 10 * cos(20)
Vx ≈ 9.40 m/s (rounded to two decimal places)
Therefore, the horizontal distance traveled by the ball will be:
dx = Vx * t
dx = 9.40 * 1.17
dx ≈ 11.0 m (rounded to one decimal place)
Hence, the ball will hit the ground approximately 11.0 meters horizontally from your window.