The heat of neutralisation of LiOH and HCL at 25 degree celsius is 34.868 kJ/mol.The heat of ionisation of LiOH will be ?

To find the heat of ionization of LiOH, we need to understand the concept of heat of neutralization and the reaction involved.

The heat of neutralization is the energy released or absorbed when one mole of an acid reacts with one mole of a base to form a salt and water. In this case, LiOH (base) reacts with HCl (acid) to form LiCl (salt) and water.

Given:
Heat of neutralization of LiOH and HCl = 34.868 kJ/mol

From this information, we can infer that 34.868 kJ of heat is released when one mole of LiOH reacts with one mole of HCl.

Now, let's focus on the heat of ionization of LiOH. The heat of ionization refers to the energy required to completely dissociate one mole of a compound into its constituent ions.

The reaction for the ionization of LiOH can be represented as:
LiOH(s) → Li+(aq) + OH-(aq)

Since LiOH is a strong base, it completely dissociates into Li+ and OH- ions when dissolved in water. Therefore, we can assume that there is no energy absorbed or released during this process.

Hence, the heat of ionization of LiOH is considered to be zero (0 kJ/mol).

So, the heat of neutralization of LiOH and HCl at 25 degrees Celsius (34.868 kJ/mol) does not provide any information about the heat of ionization of LiOH.