In 1993, the life expectancy of males in a certain country was 62.1 years. In 1997, it was 65.8 years. Let E represent the life expectancy in year t and let t represent the number of years since 1993. The linear function E(t) that fits the data is

E(t)= --- t+----
I NEED PLEASE!!!!!

let 1963 correspond with t=0

then 1997 corresponds with t=4
so you have two points (0,62.1) and (4,65.8)

find the slope and then the equation in the usual way
I get E(t) = 3.7t + 62.1

To find the linear function that fits the given data, we can use the equation of a straight line, which is in the form y = mx + b, where m is the slope of the line and b is the y-intercept.

Here, we are given two data points: (1993, 62.1) and (1997, 65.8).

To find the slope, we use the formula:
m = (y2 - y1) / (x2 - x1)

Substituting the values, we get:
m = (65.8 - 62.1) / (1997 - 1993)
m = 3.7 / 4
m = 0.925

Now that we have the slope, we can find the y-intercept (b) by substituting one of the given data points into the equation y = mx + b. Let's choose (1993, 62.1):
62.1 = 0.925 * 1993 + b

Now, we can solve for b:
b = 62.1 - 0.925 * 1993
b = -1831.575

Therefore, the linear function E(t) that fits the data is:
E(t) = 0.925t - 1831.575