Maths

object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula
h(t)=−16t^2+v0t+h0 feet
where t is the amount of time in seconds after the ball was thrown. Also, the velocity of the object is given by
v(t)=−32t+v0. feet per second

When one uses the metric system, the equations become
h(t)=−4.9t^2+v0t+h0 meters
and
v(t)=−9.8t+v0 meters per second.



An object is projected upward from a height of 33 feet at a velocity of 97 feet per second.


Find the velocity of the object when it hits the ground.

asked by Ayvar
  1. the same as when it went up.

    posted by Steve
  2. oops. not so, due to h0

    so, find t when h(t)=0
    then use that to get v(t) at that time.

    posted by Steve

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math

    In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of
  2. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the
  3. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the
  4. math

    Baseball Nick throws a baseball upward with an initial velocity of 60 feet per second. What is the maximum height of the ball after Nick releases the ball? Formula for the problem - h(t)=v0t-16t^2, h(t)= the height of an object in
  5. Math 1105

    - The heights of a ball (in feet) thrown with an initial velocity of 90 feet per second from an initial velocity of 90 feet per second from an initial height of 4 feet is given as a function of time t(in seconds)by s(t)=
  6. Pre-cal

    A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2 projectile formula: s(t)=1/2gt^2+v+t+h g=acceleration due to
  7. ap calculus

    The height s of a ball, in feet, thrown with an initial velocity of 112 feet per second from an initial height of 6 feet is given as a function of time t (in seconds) by s(t)=-16t^2+112t+20. 1. What is the maximum height of the
  8. Calculus

    A ball is thrown straight up from the top of a hill 30 feet high with an initial velocity of 72ft/sec. How high above level ground will the ball get? (Objects subjected to gravity adhere to s(t) = -16t^2 + v0t + so where s is the
  9. Algebra

    A ball is thrown in an upward direction off a platform that is 45 feet high with an initial velocity of 60 feet per second. The height, in feet, of the ball at the time t is given by h(t)= -16t^2 + 60t + 45. The time, t, is given
  10. math

    An object that is falling or vertically projected into the air has it height, in feet, above the ground given by the formula below, where s is the height in feet, Vo is the original velocity of the object, in feet per second, t is

More Similar Questions