Math, Precalc

Find values of the constants A, B, and C such that
(16x^2+48x−216)/(x^3−36x)=A/(x−6)+B/(x)+C/(x+6).

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  1. just place the right side over a common denominator and equate the coefficients of the polynomials. You will get three equations in A,B,C. Solve them to get (9,6,1)

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