The ramp rises 20 from the ground and a vertical distance of 30 inches . how much horizontal distance does the ramp cover

The ramp rises 20° from the ground and a vertical distance of 30 inches. How much horizontal distance does the ramp cover? Round to the nearest tenth.

huh? If 20 is not the vertical, what is it?

maybe the horizontal distance is √(30^2 - 20^2)

Hard to tell from your garbled posting.

well if you're going to be rude... you might as well get off this site.

To find the horizontal distance covered by the ramp, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this scenario, the vertical height of the ramp is given as 30 inches, and the ramp is inclined at an angle with respect to the ground. Let's call the horizontal distance covered by the ramp "x."

Using the Pythagorean theorem, we have:

(20)^2 + x^2 = (30)^2

Simplifying, we get:

400 + x^2 = 900

Rearranging the equation, we have:

x^2 = 900 - 400

x^2 = 500

Taking the square root on both sides, we get:

x = √500

Therefore, the horizontal distance covered by the ramp is approximately 22.36 inches.