0.4 moles of pcl3 and 0.3 moles of pcl3 added to access ofC2H5OH then maximum no of moles obtained
To find the maximum number of moles obtained in a reaction between 0.4 moles of PCl3 and 0.3 moles of C2H5OH, we need to determine the limiting reagent.
1. Write the balanced chemical equation for the reaction:
PCl3 + C2H5OH -> PCl3OH + C2H5Cl
2. Calculate the moles-to-moles ratio between the two reactants:
PCl3 : C2H5OH = 1 : 1
3. Compare the moles available to the stoichiometric ratio:
The available moles of PCl3 is 0.4 and the available moles of C2H5OH is 0.3.
- If the moles of PCl3 are lower than the stoichiometric ratio (0.4 < 1), PCl3 is the limiting reagent.
- If the moles of C2H5OH are lower than the stoichiometric ratio (0.3 < 1), C2H5OH is the limiting reagent.
4. Since the moles of both reactants are above the stoichiometric ratio, neither is the limiting reagent, and both will be fully consumed in the reaction.
5. Calculate the moles of the product formed using the limiting reagent:
For every 1 mole of PCl3 reacted, 1 mole of PCl3OH is formed.
For every 1 mole of C2H5OH reacted, 1 mole of C2H5Cl is formed.
Therefore, the maximum number of moles obtained will be equal to the number of moles used by the limiting reagent.
In this case, since both reactants are fully consumed, the maximum number of moles obtained will be the same as the limiting reagent.
So, the maximum number of moles obtained will be 0.3 moles.