Na2CO3(aq)+ 2HNO3(aq)--> 2NaNO3+H2O(l)+CO2(g)
how do I get net ionic?
To obtain the net ionic equation, you need to start with the balanced molecular equation and then identify the spectator ions by canceling out any ions that appear on both sides of the equation.
Here's the step-by-step process:
Step 1: Write the balanced molecular equation.
Na2CO3(aq) + 2HNO3(aq) → 2NaNO3(aq) + H2O(l) + CO2(g)
Step 2: Write the ionic equation by breaking down all the soluble compounds into their respective ions.
Na2CO3(aq) + 2H+(aq) + 2NO3-(aq) → 2Na+(aq) + 2NO3-(aq) + H2O(l) + CO2(g)
Step 3: Identify the spectator ions. Spectator ions are ions that appear on both sides of the equation and do not participate in the overall reaction. In this case, the Na+ and NO3- ions are present on both sides.
Step 4: Write the net ionic equation by canceling out the spectator ions.
H+(aq) + CO3^2-(aq) → H2O(l) + CO2(g)
So, the net ionic equation for the reaction of Na2CO3(aq) and 2HNO3(aq) is H+(aq) + CO3^2-(aq) → H2O(l) + CO2(g).
To obtain the net ionic equation from the given balanced chemical equation, you need to first write the complete ionic equation. Then you can cancel out the spectator ions to obtain the net ionic equation.
Step 1: Write the balanced complete ionic equation
Na2CO3(aq) + 2HNO3(aq) → 2NaNO3(aq) + H2O(l) + CO2(g)
In the complete ionic equation, every soluble ionic compound dissociates into its respective ions. Therefore, we can write the equation with the dissociated ions:
2Na+(aq) + CO3^2-(aq) + 2H+(aq) + 2NO3^-(aq) → 2Na+(aq) + 2NO3^-(aq) + H2O(l) + CO2(g)
Step 2: Cancel out the spectator ions
In the complete ionic equation, the sodium ions (Na+) and nitrate ions (NO3-) appear on both sides of the equation and do not participate in the reaction. These ions are called spectator ions. In the net ionic equation, we remove the spectator ions.
CO3^2-(aq) + 2H+(aq) → H2O(l) + CO2(g)
Therefore, the net ionic equation for the given reaction is CO3^2-(aq) + 2H+(aq) → H2O(l) + CO2(g).