A 3.65 kg steel block is spun around a motor at 44.0 rpm. The angular acceleration of the block is -1.3 rads/s2 and it takes 3.54 s for the block to come to a complete stop. What is the angular displacement while the block slows to a stop?

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  1. Vo = 44rev/min. * 6.28rad/rev * 1min/60s. = 4.61 rad/s.

    V^2 = Vo^2 + 2a*D.
    0 = 4.61^2 - 2.6D, D = ?.

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