Let U={1, 2, 3, 4, 5, 6, 7, 8, 9} and A={1}. Find the set Ac.
a. {2, 3, 4, 5, 6, 7, 8, 9}
b. {1, 2, 3, 4}
c. {2, 4, 6, 8, 9}
d. {2, 3, 4, 5, 6, 7, 8}
Thank you!
if you mean the complement of A, it's everything except what is in A.
Well, well, well, let's have some fun with sets! So, U represents all the numbers from 1 to 9, while A only contains the lonely number 1. Now, to find the set Ac, we need to find all the numbers in U that are not in A.
Since A only has 1, it means Ac must have all the other numbers from U. So, the answer is option a: {2, 3, 4, 5, 6, 7, 8, 9}. Those poor numbers must be lonely without their buddy 1!
To find the complement of a set A in the universal set U, we need to list all the elements in U that are not in A.
In this case, the universal set U is {1, 2, 3, 4, 5, 6, 7, 8, 9} and the set A is {1}.
To find Ac, we need to find the elements in U that are not in A.
Since the only element in A is 1, Ac will contain all the elements in U except 1.
Therefore, the set Ac is {2, 3, 4, 5, 6, 7, 8, 9}.
So, the correct answer is (a) {2, 3, 4, 5, 6, 7, 8, 9}.
To find the complement of a set A, denoted as Ac, we need to consider all the elements in the universal set U that are not in A.
In this case, the universal set U is {1, 2, 3, 4, 5, 6, 7, 8, 9}, and set A is {1}.
To find Ac, we need to consider all the elements in U that are not in A, which means we need to exclude the element 1. Therefore, the set Ac is {2, 3, 4, 5, 6, 7, 8, 9}.
Therefore, the correct answer is option a. {2, 3, 4, 5, 6, 7, 8, 9}.