station A and station B apart from rest st station A and acceleration at A constants rate of a=1.2 m.s.s
until the mid point to station B it slows down at the same rate a and stop at b final?
a) the time of train between station ?
b)The maximum speed of the train?
geez - same problem, no fixes made.
I think you need the distance between A and B. Lets call the distance x.
V(x/2)^2=2 a (x/2)
or v at half way is sqrt(2*1.2)(x^2/4)
so v average for the first half trip is half that, or
vavg=sqrt(2*1.2*x^2/16)
but this is the same average speed on the second half...
so time=x/vavg=x/sqrt(2.4x^2/16)
= x^2/4 sqrt (2.4)
max speed? we did that first.
To find the answers to these questions, we need to use the equations of motion.
a) The time it takes for the train to travel between station A and station B can be found using the equation:
t = (v - u) / a
Where:
t = time
v = final velocity of the train
u = initial velocity of the train
a = acceleration
In this case, since the train starts from rest at station A and stops at station B, the initial velocity (u) is 0 m/s, the final velocity (v) is also 0 m/s, and the acceleration (a) is 1.2 m/s^2.
Plugging these values into the equation, we get:
t = (0 - 0) / 1.2
Since the numerator is zero, the time it takes for the train to travel between station A and station B is also zero. This means that the train stops instantly at station B.
b) The maximum speed of the train can be found using the equation:
v = u + at
Where:
v = final velocity of the train
u = initial velocity of the train
a = acceleration
t = time
In this case, since the train starts from rest at station A and stops at station B, the initial velocity (u) is 0 m/s, the final velocity (v) is also 0 m/s, and the acceleration (a) is 1.2 m/s^2.
Plugging these values into the equation, we get:
0 = 0 + 1.2t
Simplifying the equation, we find:
t = 0
Since the time (t) is zero, it means that the train does not reach any maximum speed between station A and station B. The train starts from rest, accelerates at a constant rate, and stops at station B.