the sum of two numbers is 31. 2/3 of one of the numbers added is equal to 5/8 of the other.find the two numbers
n + m = 31
2n/3 ÷ 5m/8
3/2× 5/8 = 15m/16n
15m +16n= 31
Answer= 15,16
This is the correct answer
(2/3)x = (5/8)(31-x)
Thanks so much i got it
⅔x*⅝y=31
Cross multiply
15x+16y=31
The Answer is 15x,16y
thanks a lot.
thanks a lot
The sum of two numbers is 31.2/3 of one of the numbers is equal to 5/8 .find the two numbers
To find the two numbers, let's assign variables to them. Let's say one number is x and the other number is y.
From the problem, we know that the sum of the two numbers is 31. So we can write the equation:
x + y = 31
We are also given that 2/3 of one of the numbers added to the other number is equal to 5/8 of the other number. So we can write the equation:
(2/3)x + y = (5/8)y
Now we have a system of equations with two variables (x and y). We can solve this system of equations using substitution or elimination.
Let's use substitution method to solve the system:
Rearrange the first equation to solve for x:
x = 31 - y
Substitute this value of x in the second equation:
(2/3)(31 - y) + y = (5/8)y
Multiply through by 24 to get rid of fractions:
16(31 - y) + 24y = 15y
Distribute and simplify:
496 - 16y + 24y = 15y
496 + 8y = 15y
496 = 7y
y = 496/7
y = 71.14 (rounded to two decimal places)
Substitute this value of y back into the first equation to find x:
x + 71.14 = 31
x = 31 - 71.14
x = -40.14 (rounded to two decimal places)
So, the two numbers are approximately -40.14 and 71.14.