a marathoner ran the 26.2-mi New York City marathon in 2.2h. show that at least twice, the marthoner was running at exactly 11 mph
the average is 26.2/2.2=11.9mph
Didnt the runner have to stop and start?
show that the solution has exactly one solution in the interval
x+ln(x+1)=0, 0<and equal to x <and equal to 3
9=0
12
To show that the marathoner ran at exactly 11 mph at least twice during the race, we can use the concept of average speed.
Average speed is defined as the total distance traveled divided by the total time taken.
In this case, the marathoner ran a distance of 26.2 miles in a total time of 2.2 hours.
Average Speed = Total Distance / Total Time
Average Speed = 26.2 miles / 2.2 hours
Average Speed = 11.91 mph (rounded to two decimal places)
Since the average speed is approximately 11.91 mph, we can conclude that at some point during the marathon, the runner must have been running at an exact speed of 11 mph for a certain period of time. Additionally, since the average speed is greater than 11 mph, it indicates that the runner was running at 11 mph at least twice, as there were moments when the runner was running faster than 11 mph, which influenced the average speed to be slightly higher.