Physics

A football quarterback shows off his skill by throwing a pass 45.90 m downfield and into a bucket. The quarterback consistently launches the ball at 40.00 ∘ above horizontal, and the bucket is placed at the same level from which the ball is thrown.
What initial speed is needed so that the ball lands in the bucket?

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asked by Lily
  1. s = speed

    45.9 = u T
    where
    u = s cos 40
    so
    T = 45.9 /(s cos 40) where T is time aloft

    rise time is half T or t = T/2
    v = Vi - g t
    Vi = s sin 40
    at top v = 0
    s sin 40 = 9.81 t = 9.81[45.9/(2s cos 40]
    or
    2 s^2 sin 40 cos 40 = 9.81*45.9

    remember trig now

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    posted by Damon
  2. 6

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    posted by Anonymous
  3. Similarly, when you solve for m = 46, you get:

    2 s^2 sin 40 cos 40 = 9.81*46
    s = 21.40 m/s

    You're welcome.

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    posted by Anonymous

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