A 15 g bullet is fired from a gun of mass 2kg with a speed of look m/s . Find the recoil velocity of the gun.
since mv is the same for both bodies,
m1/m2 = v2/v1
15/2000 = v2/v1
Now if you can see your way to specifying v1, you can find v2.
To find the recoil velocity of the gun, we can apply the principle of conservation of momentum.
According to the conservation of momentum, the total momentum before the bullet is fired is equal to the total momentum after the bullet is fired. Momentum is defined as the product of mass and velocity.
Let's denote the mass of the bullet as m1, the velocity of the bullet as v1, the mass of the gun as m2, and the recoil velocity of the gun as v2.
Given:
Mass of the bullet, m1 = 15 g = 0.015 kg
Velocity of the bullet, v1 = 400 m/s (you mentioned "look m/s," so I'll assume it's 400 m/s)
Mass of the gun, m2 = 2 kg
We know that momentum is conserved, so we can write the equation as:
(mass of bullet * velocity of bullet) + (mass of gun * velocity of gun) = 0
(m1 * v1) + (m2 * v2) = 0
Therefore,
(0.015 kg * 400 m/s) + (2 kg * v2) = 0
1.5 kg*m/s + (2 kg * v2) = 0
To solve for v2, we rearrange the equation:
2 kg * v2 = -1.5 kg * m/s
v2 = (-1.5 kg * m/s) / (2 kg)
v2 = -0.75 m/s
So, the recoil velocity of the gun is -0.75 m/s. The negative sign indicates that the gun moves in the opposite direction of the bullet.