A model car travels horizontally after being released. The car travels a distaance d metres in a time of t seconds. d is directly proportional to t. The car travels 20 metres in a time of 2 seconds. A.Calculate the distance the car travels in 3 seconds.

20/2 = 10 meters per second

Calculate the time the car takes to travel 605m what answer

To solve this problem, we need to find the constant of proportionality between distance and time using the information given.

From the problem, we know that the car travels 20 meters in 2 seconds. This means that the ratio of distance to time remains the same. Let's use this information to solve for the constant of proportionality.

Let d1 be the distance traveled in 20 meters in 2 seconds.
Let t1 be the time taken, which is 2 seconds.

According to the problem, we can set up the following equation:
d1/t1 = k, where k represents the constant of proportionality.

Substituting the values of d1 = 20 meters and t1 = 2 seconds into the equation, we have:
20/2 = k
10 = k

Now we have the value of k, which is 10. This means that the distance traveled is directly proportional to time, where for every 1-second increase in time, the car will travel an additional 10 meters.

To find the distance the car travels in 3 seconds, let's use this constant of proportionality.

Let t2 be the new time, which is 3 seconds.
Let d2 be the distance traveled in 3 seconds.

Using the equation d1/t1 = d2/t2, we can substitute the known values:
20/2 = d2/3

Solving for d2, we can cross-multiply and divide:
2 * d2 = 20 * 3
2d2 = 60
d2 = 60/2
d2 = 30 meters

Therefore, the car will travel 30 meters in 3 seconds.

To calculate the distance the car travels in 3 seconds, we can use the concept of direct proportionality.

First, we need to establish the relationship between the distance (d) and time (t) based on the given information. We are told that d is directly proportional to t, which means that we can express this relationship as:

d ∝ t

Using the values provided, we have:

d = 20 metres (distance)
t = 2 seconds (time)

Now, we need to find the constant of proportionality (k) to relate d and t. We can find the value of k by dividing the distance by the time:

k = d / t

k = 20 metres / 2 seconds

k = 10 metres/second

Now that we have determined the value of k, we can use it to find the distance the car travels in 3 seconds.

Let's substitute the given value of t = 3 seconds into the proportional relationship:

d = k * t

d = 10 metres/second * 3 seconds

d = 30 metres

Therefore, the car will travel a distance of 30 metres in 3 seconds.