In a reversible reaction PCl5 ↔ PCl3 + Cl2, the value of K is 2.5. What will the partial pressure of Cl2 be?

To determine the partial pressure of Cl2 in the given reversible reaction, we need to use the equilibrium constant (K) and the initial concentrations or partial pressures. The formula to calculate the equilibrium constant (K) for gas-phase reactions is expressed in terms of partial pressures:

K = (Partial pressure of PCl3 * Partial pressure of Cl2) / (Partial pressure of PCl5)

Here, we are given the value of K (2.5). However, in order to calculate the partial pressure of Cl2, we need the initial concentrations or partial pressures of PCl5 and PCl3.

Without the initial concentrations or partial pressures, it is not possible to determine the exact value of the partial pressure of Cl2.

I don't think you have enough information. How much PCl5 do you have (pressure or M)?