chemistry

A Li2+ ion had its electron in an excited state. When the electron relaxed to the ground state (n = 1) a photon of light was emitted with an energy of 1.884×10−17 J. What energy level was the electron in before it transitioned to the ground state?

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  1. (1/wavelength) = RZ^2(1/n^2 - 1/n^2)
    (1/wavelength) = RZ^2*(1/1^2 - 1/x^2) and solve for x.
    R = Rydberg constant = 1.0973732
    The first n is n = 1 and the second n is n = 2; that's where the 1/1^2 and 1/x^2 come from.
    Z is the atomic number of the element; in this case that is 3 so Z^2 = 9.
    You will need to convert energy to wavelength with E = hc/wavelength. Post your work if you get stuck.

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