Length of a rectangle is 16 centimetre less than twice its breadth if the perimeter of a rectangle is 100 centimetre find its length and breadth
L=28CM,B=22CM
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To find the length and breadth of a rectangle, we can set up some equations based on the given information.
Let's assume the breadth of the rectangle is 'x' centimeters.
According to the problem, the length is 16 centimeters less than twice the breadth.
So, the length would be (2x - 16) centimeters.
The perimeter of a rectangle is given by the formula: P = 2(l + b), where P is the perimeter, l is the length, and b is the breadth.
In this case, the perimeter is given as 100 centimeters, so we can substitute these values into the formula:
100 = 2((2x - 16) + x)
Now, we can simplify and solve the equation to find the value of 'x', which represents the breadth of the rectangle.
100 = 2(3x - 16)
100 = 6x - 32
6x = 100 + 32
6x = 132
x = 132/6
x = 22
Now that we have the value of 'x', we can substitute it back into the equation for the length to find its value:
Length = 2x - 16
Length = 2(22) - 16
Length = 44 - 16
Length = 28
Therefore, the length of the rectangle is 28 centimeters and the breadth is 22 centimeters.
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L = 2w -16
2L + 2W = 100
substitute for "l"
2(2w-16) + 2w = 100
4w -32 + 2w =100
6w = 132
Can you finish from here?