A 95.00 kg man on ice skates catches a ball moving at 18 m/s. The man is initially at rest. The man and the ball move together after the collision. The ball's mass is 0.14 kg. What is the final velocity

conserve momentum:

Is the ball stationary, moving directly away/toward him?

Pick your answer, and then just write the momentum equations before and after collision. Solve for v.

j

To find the final velocity of the man and the ball after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The total momentum before the collision is calculated by multiplying the mass of the man by his initial velocity, and adding it to the product of the mass of the ball and its initial velocity. Since the man is initially at rest, his initial velocity is 0 m/s. Thus, the total momentum before the collision is (0 kg)(0 m/s) + (0.14 kg)(18 m/s) = 0 kg·m/s + 2.52 kg·m/s = 2.52 kg·m/s.

The total momentum after the collision is calculated by multiplying the combined mass of the man and the ball by their final velocity. Let's call the final velocity v_f. The combined mass of the man and the ball is 95.00 kg + 0.14 kg = 95.14 kg. Therefore, the total momentum after the collision is (95.14 kg)(v_f).

Since the total momentum before the collision is equal to the total momentum after the collision, we can set up the following equation:

2.52 kg·m/s = (95.14 kg)(v_f)

Now we can solve for the final velocity, v_f:

v_f = 2.52 kg·m/s / 95.14 kg
v_f ≈ 0.0265 m/s

Therefore, the final velocity of the man and the ball after the collision is approximately 0.03 m/s.