Algebra 2

Given: 11-pound mixture of peanuts, almonds, and raisins
Cost:
peanuts - 1.5 per pound
almonds - 3 per pound
raisins - 1.5 per pound

mixture:
twice as many peanuts as almond; total cost of mixture is 21.

a + p + r = 11 lbs
a + 2a + r = 11 lbs
3a + r = 11
r = 11 - 3a

1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
1.5a/1.5 = 4.5/1.5
a = 3

almonds = 3 lbs
peanuts = 2a = 2(3) = 6lbs
raisins = 11 - 3a = 11 - 3(3) = 11 - 9 = 2 lbs

My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

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  1. You can easily check this yourself.
    First
    3 + 6 + 2 = 11 sure enough
    twice as many peanuts as almonds, yes

    total cost = 1.5*6 + 3*3 + 1.5*2
    = 9 + 9 + 3 = 21 so yes, done

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  2. what's the answer to the rest of the quiz???

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