a spinner is split into three equal sections numbered one through three. What is the probability of spinning two threes in a row?

I am doing this problem now and I really don't get it

the answer is 1/9

A spinner has three equal sections numbered 1, 2 and 3. You spin it twice. Find a. Spinning al and then a 3. b. Spinning a 3 and then an even number.​

To find the probability of spinning two threes in a row on a spinner divided into three equal sections numbered one through three, let's break down the problem step by step.

Step 1: Determine the total number of possible outcomes.
The spinner is divided into three equal sections, so there are three possible outcomes for each spin. Since we are spinning the spinner twice, the total number of possible outcomes is 3 multiplied by 3, which equals 9.

Step 2: Determine the favorable outcomes.
To spin two threes in a row, you need to spin a three on the first spin and then another three on the second spin. Since there is only one section on the spinner marked with a three, the favorable outcome is just 1.

Step 3: Calculate the probability.
The probability is the ratio of favorable outcomes to total outcomes. In this case, the probability of spinning two threes in a row is 1 (favorable outcomes) divided by 9 (total outcomes).

P(2 threes in a row) = 1/9

Therefore, the probability of spinning two threes in a row is 1/9.

I don't understand the question and I'm really confused.

1/6 because there are three different possibilities and u are spinning it twice so 3+3=6 and that is 1/6