If 20 grams of zinc reacts with hydrochloric acid, how much zinc chloride is produced?
Okay. First make your balanced equation:
Zn+2HCL-->ZnCl2+2H
Now. there is excess HCL. That means Zn is your limiting reactant. So the find out zinc chloride in your stoichiometry you must use Zn.
The work:
g ZnCl2=(20 g Zn)(1 mole Zn/65.39g)(1 mole ZnCl2/1 mole Zn)(136.29g ZnCl2/1 mole)=40 grams.
The real answer is 41.68527298, but using the proper sig fig is 40 grams because 20 only has 1 sig fig (2).
Hope that helps!
The answer by Ashley is correct but the equation is not. Here is the correct equation.
Zn + 2HCL-->ZnCl2 + H2
To determine the amount of zinc chloride produced, you need to calculate the stoichiometric ratio between zinc and zinc chloride using the balanced chemical equation. Assuming that the reaction goes to completion, the balanced equation for the reaction between zinc and hydrochloric acid is:
Zn + 2HCl -> ZnCl2 + H2
According to the equation, 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride. The molar mass of zinc is approximately 65.38 g/mol, and the molar mass of zinc chloride is approximately 136.29 g/mol.
To determine the number of moles of zinc, you need to divide the mass of zinc (20g) by the molar mass of zinc:
Number of moles of zinc = Mass of zinc / Molar mass of zinc
= 20g / 65.38 g/mol
≈ 0.306 moles
Since the stoichiometric ratio between zinc and zinc chloride is 1:1, the number of moles of zinc chloride produced will be equal to the number of moles of zinc.
Number of moles of zinc chloride = 0.306 moles
Finally, to find the mass of zinc chloride produced, you need to multiply the number of moles of zinc chloride by the molar mass of zinc chloride:
Mass of zinc chloride = Number of moles of zinc chloride × Molar mass of zinc chloride
= 0.306 moles × 136.29 g/mol
≈ 41.73 grams
Therefore, approximately 41.73 grams of zinc chloride will be produced when 20 grams of zinc reacts with hydrochloric acid.
To determine the amount of zinc chloride produced when 20 grams of zinc reacts with hydrochloric acid, you need to consider the balanced chemical equation for the reaction:
Zn + 2HCl → ZnCl₂ + H₂
According to the equation, 1 mole of zinc (Zn) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of zinc chloride (ZnCl₂) and 1 mole of hydrogen gas (H₂).
To find the amount of zinc chloride produced, you can follow these steps:
1. Convert the mass of zinc (20 grams) to moles:
The molar mass of zinc is 65.38 g/mol (you can find this value on the periodic table).
Therefore, 20 grams of zinc is equal to 20 g / 65.38 g/mol = 0.305 moles of Zn.
2. Determine the stoichiometric ratio between zinc and zinc chloride:
According to the balanced equation, 1 mole of Zn produces 1 mole of ZnCl₂.
Hence, 0.305 moles of Zn will produce 0.305 moles of ZnCl₂.
3. Convert the moles of zinc chloride to grams:
The molar mass of zinc chloride (ZnCl₂) is 136.29 g/mol (again, you can find this value on the periodic table).
Therefore, 0.305 moles of ZnCl₂ is equal to 0.305 mol * 136.29 g/mol = 41.61 grams of ZnCl₂.
Thus, when 20 grams of zinc reacts with hydrochloric acid, it produces approximately 41.61 grams of zinc chloride.