Ethyl alcohol has a heat of vaporization of 850. J/g. What mass of ethyl alcohol can be boiled using 15000 J of energy?
q = mass ethyl alcohol x heat vap
I think I got 300/17, but another time I got plain old 17....
To find the mass of ethyl alcohol that can be boiled using 15000 J of energy, we need to use the formula:
Q = m * ΔHv
Where:
Q is the energy input (15000 J),
m is the mass of the substance,
ΔHv is the heat of vaporization (850 J/g).
Rearranging the formula to solve for mass (m):
m = Q / ΔHv
Substituting the given values:
m = 15000 J / 850 J/g
m ≈ 17.65 g
Therefore, approximately 17.65 grams of ethyl alcohol can be boiled using 15000 J of energy.
To find the mass of ethyl alcohol that can be boiled using 15000 J of energy, we need to use the equation:
Heat of vaporization = Energy / Mass
Rearranging the equation to solve for mass, we have:
Mass = Energy / Heat of vaporization
Plugging in the given values, we get:
Mass = 15000 J / 850 J/g
Calculating this division, we find:
Mass = 17.65 g
Therefore, using 15000 J of energy, we can boil approximately 17.65 grams of ethyl alcohol.