A student melts 50.0 grams of ice using 16650 J of energy. What is the heat of fusion of ice?
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4.23
To find the heat of fusion of ice, we can use the following equation:
Q = m * Hf
Where:
Q = amount of heat absorbed or released during a phase change (in joules)
m = mass of the substance (in grams)
Hf = heat of fusion (in J/g)
Given:
m = 50.0 grams
Q = 16650 J
Rearranging the equation:
Hf = Q / m
Plugging in the given values:
Hf = 16650 J / 50.0 g
Calculating the value:
Hf = 333 J/g
Therefore, the heat of fusion of ice is 333 J/g.
To find the heat of fusion of ice, we can use the equation:
Heat = mass * heat of fusion
First, we need to find the mass of the ice that melted. The given mass of the ice is 50.0 grams.
Next, we can use the equation:
Energy = mass * specific heat * change in temperature
Since the ice is melting, the change in temperature is zero (0°C to 0°C). We can rearrange the equation to solve for the mass:
mass = energy / (specific heat * change in temperature)
The specific heat of ice is approximately 2.09 J/g°C.
mass = 16650 J / (2.09 J/g°C * 0°C)
mass = 16650 J / 0 J/g
mass = ∞ (infinity)
From this calculation, we can see that the mass of the ice is irrelevant since it cancels out in our equation.
Therefore, the heat of fusion of ice is 16650 J (since the mass of the ice did not affect the result).