What volume (in mL) of a 0.750M solution of hydrochloric acid can produced by the reaction of 25.0g of NaCl with an excess of sulfuric acid? NaCl+H2SO4= HCl+ NaHSO4
To solve this question, you need to use the concept of stoichiometry and the relationship between the given substances in the balanced chemical equation.
First, let's find the number of moles of NaCl using its molar mass. The molar mass of NaCl is 58.44 g/mol.
Number of moles = mass/molar mass
Number of moles of NaCl = 25.0 g / 58.44 g/mol ≈ 0.428 moles
From the balanced chemical equation, we can see that 1 mole of NaCl reacts to produce 1 mole of HCl. Therefore, the number of moles of HCl produced will also be 0.428 moles.
Now, we can use the molarity of the HCl solution to find the volume of the solution.
Molarity (M) = moles of solute/volume of solution (in liters)
0.750 M = 0.428 moles / volume (in liters)
Rearranging the equation, we can find the volume in liters:
Volume (in liters) = moles of solute / molarity
Volume (in liters) = 0.428 moles / 0.750 M ≈ 0.570 liters
Finally, we need to convert the volume from liters to milliliters:
Volume (in mL) = 0.570 liters x 1000 mL/liter = 570 mL
Therefore, the volume of the 0.750 M solution of hydrochloric acid that can be produced from the reaction is approximately 570 mL.