Question

y=log(logx) sir this question answer 1/x log x

Answer 1

Use chain rule:

dy / dx = ( dy / du ) * ( du / dx )

u = log x

y = log ( log x ) = log u

dy / du = d ( log u ) / du =

1 / u = 1 / log x

( du / dx ) = d ( log x ) / dx = 1 / x

dy / dx = ( dy / du ) * ( du / dx ) =

( 1 / log x ) * ( 1 / x ) =

1 / x log x