A 550 N crate rests on the floor. How much work in joules is required to move it at constant speed 7.0 m along the floor, against a friction force of 150 N?
Fap-Fc-Fs = M*a.
Fap-550-150 = M*0 = 0, Fap = 700 N. = Force applied.
W0rk = Fap*d = 700 * 7.0 = 4900 J.
To find the work required to move the crate at a constant speed against the friction force, we can use the formula:
Work = Force × Distance
The force in this case is the force required to overcome friction, which is given as 150 N. The distance is given as 7.0 m. Plugging these values into the formula, we get:
Work = 150 N × 7.0 m
Calculating this expression, we find:
Work = 1050 N⋅m
However, the unit for work is Joules (J), not N⋅m. Since 1 Joule is equivalent to 1 N⋅m, we can conclude that the work required to move the crate is 1050 Joules.
To calculate the work required to move the crate at a constant speed against the friction force, we can use the formula:
Work = Force x Distance
In this case, the force opposing the movement is the friction force of 150 N, and the distance moved is 7.0 m. Therefore, we have:
Work = 150 N x 7.0 m
Now, let's calculate:
Work = 1050 N·m
To convert this to joules, we need to use the conversion factor:
1 joule = 1 N·m
Therefore, the work required to move the crate is:
Work = 1050 N·m = 1050 joules
So, the work required to move the crate at a constant speed of 7.0 m along the floor against the friction force of 150 N is 1050 joules.
Correction: Fap-Fs = M*a.
Fap = M*0 + 150 = 150 N. = Force applied.
Work = Fap*d = 150 * 7 = 1050 J.