# math

How many liters each of a 55% acid solution and a 80% acid solution must be used to produce 50 liters of a 60% acid solution? (Round to two decimal places if necessary.)

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1. If there are x liters of the 55%, then the rest (50-x) is 80%.

SO, now just add up the acid in the parts -- it must equal the acis in the final mix:

.55x + .80(50-x) = .60*50

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