1. Suppose that 10.2 mL of 0.0512 M NaOH were required to titrate a sample of unkown acid. How many moles of NaOH were used?
mols = M x L = ?
only part of my answer was posted. The real question is: Assuming that the unknown acid sample in question 1 has a mass of 0.177g, what is the molar mass of the unknown? I tried moles = Grams/Molar Mass, but the answer is saying incorrect.
I don't see any answer you posted; I see only questions.
NaOH + HA ==> NaA + H2O
1 mol NaOH = 1 mol HA so
mols NaOH from above = mols HA.
Then mols = grams/molar mass or
molar mass = grams/mols. If you did g/mols, I suggest you post your work and let us look at it.
To determine the number of moles of NaOH used, you need to multiply the volume of NaOH (in liters) by its molarity. Here's how you can calculate it step by step:
Step 1: Convert the volume of NaOH from milliliters (mL) to liters (L).
To do this, divide the volume in mL by 1000:
10.2 mL ÷ 1000 = 0.0102 L
Step 2: Calculate the moles of NaOH using the volume and molarity.
Multiply the volume (in liters) by the molarity:
0.0102 L × 0.0512 mol/L = 0.0005232 moles
Therefore, 0.0005232 moles of NaOH were used in the titration.