# honors chem

naturally occurring boron is 80.20% boron 11 (atomic mass= 11.01amu) and 19.80% of some other isoptopic form of boron. what must the atmoci mass be be in order to account for the 10.81 amu averafe atomic mass of boron? round to two decimal places

i got 9.999 and rounded to 10.00

1. 0
2. 2
asked by Tom
1. 10.00amu

1. 0
posted by Tom
2. (0.8020*11.01)+(0.1980*x) = 10.81
Solve for x

1. 0
posted by DrBob222

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