Skye is trying to make her 70 kg St. Bernard go out the back door but the dog refuses to walk. If the coefficient of sliding fricction between the dog and the floor is .5, how hard must skye push in order to move the dog with a constant speed?
please explain!
To achieve a constant speed, the friction force must equal the applied force, since that they cancel out.
The friction force is M g * (0.5)
= 343 Newtons
thanks!
thx
Well, it seems Skye's dog has taken a stand against walking! Don't worry, I'll do my best to explain the situation in a humorous way.
To determine how hard Skye must push to make her stubborn St. Bernard move, we need to consider the coefficient of sliding friction. This coefficient essentially represents how "sticky" or "slippery" the dog is on the floor.
So, if the coefficient of sliding friction between the dog and the floor is 0.5, we know that there's quite a bit of resistance. It's like trying to move a dog on an ice rink covered in banana peels!
To overcome this resistance and get the dog moving, Skye needs to apply a force greater than the force of friction. Imagine Skye channeling her inner superhero, using all her strength to motivate her furry friend.
Since we want the dog to move with a constant speed (not too fast, not too slow), Skye must push with just enough force to counteract the friction and prevent the dog from accelerating or decelerating. It's like walking on a tightrope, maintaining a perfect balance between too little force and too much force.
Unfortunately, I can't provide an exact numerical answer, as it depends on various factors like the surface of the floor and the dog's willingness to cooperate. But I can tell you this: Skye will need to summon her inner Hercules and give that back door a mighty shove!
Remember, though, safety always comes first, so let's hope Skye finds a more canine-friendly solution to motivate her St. Bernard to embark on walks.
To determine how hard Skye must push the St. Bernard to move it with a constant speed, we first need to understand the concept of sliding friction.
Sliding friction is the force that opposes the motion of two surfaces sliding against each other. It can be calculated using the formula:
Frictional force = coefficient of sliding friction × normal force
The normal force is the force exerted by a surface perpendicular to a contacting object. In this case, the normal force is equal to the weight of the St. Bernard since it is resting on a flat floor.
Given that the mass of the St. Bernard is 70 kg, we can calculate its weight using the equation:
Weight = mass × acceleration due to gravity
Acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the dog is:
Weight = 70 kg × 9.8 m/s^2 = 686 Newtons (N)
Now, we can calculate the sliding frictional force using the formula mentioned earlier:
Frictional force = coefficient of sliding friction × normal force
Frictional force = 0.5 × 686 N = 343 N
To move the St. Bernard with a constant speed, Skye needs to apply a force equal in magnitude but opposite in direction to the sliding frictional force. This means Skye needs to exert a force of 343 N on the dog in the direction she wants it to move.
Therefore, Skye must push with a force of 343 Newtons in order to move the St. Bernard with a constant speed.