Two balls of identical sizes but different masses moving exactly along the same straight line. The left ball (m = 0.5 kg) is moving with a velocity of 2 m/s to the right, and the right ball (m = 0.1 kg) is moving at 0.25 m/s to the right also. The balls collide. After the collision, the velocity of the right ball is 1.5 m/s to the right.
1. What is the kinetic energy in J of the left ball after the collision?
conservation of momentum:
.5*2+.1*.25=.5V+.1*1.5
1+.025-.15=.5V
V=2(.875)=1.75 m/s to right (which is impossible, of course as it had to just go through thr right ball going slower.
KE= 1/2 m v^2=1/2 *.5*1.75^2 J
To calculate the kinetic energy of the left ball after the collision, we need to use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the left ball is 0.5 kg and its velocity after the collision is 1.5 m/s to the right, we can substitute these values into the formula:
Kinetic Energy = (1/2) * 0.5 kg * (1.5 m/s)^2
First, let's square the velocity:
(1.5 m/s)^2 = 2.25 m^2/s^2
Next, we can substitute this value into the formula:
Kinetic Energy = (1/2) * 0.5 kg * 2.25 m^2/s^2
Now, let's simplify the calculation:
Kinetic Energy = 0.25 kg * 2.25 m^2/s^2
Kinetic Energy = 0.5625 kg⋅m^2/s^2
Therefore, the kinetic energy of the left ball after the collision is 0.5625 Joules (J).