Write each number 327 ; 792 between: two consecutive multiples of 10

round down and round up

write 327 between two consecutive multiples of 10

To write each number 327 and 792 between two consecutive multiples of 10, we first need to find those multiples.

Step 1: Find the multiple of 10 that is smaller than 327.
Divide 327 by 10: 327 ÷ 10 = 32 with a remainder of 7.
Since the remainder is 7, the nearest multiple of 10 smaller than 327 is 320.

Step 2: Find the multiple of 10 that is larger than 327.
Add 1 to the quotient obtained in step 1: 32 + 1 = 33.
Multiply this quotient by 10: 33 × 10 = 330.
So, the nearest multiple of 10 larger than 327 is 330.

Therefore, the two consecutive multiples of 10 between which 327 lies are 320 and 330.

Now, let's follow the same steps to find the multiples of 10 for the number 792.

Step 1: Find the multiple of 10 that is smaller than 792.
Divide 792 by 10: 792 ÷ 10 = 79 with no remainder.
Since there is no remainder, the nearest multiple of 10 smaller than 792 is 790.

Step 2: Find the multiple of 10 that is larger than 792.
Add 1 to the quotient obtained in step 1: 79 + 1 = 80.
Multiply this quotient by 10: 80 × 10 = 800.
Therefore, the nearest multiple of 10 larger than 792 is 800.

Hence, the two consecutive multiples of 10 between which 792 lies are 790 and 800.

In conclusion, the numbers 327 and 792 lie respectively between the consecutive multiples of 10: 320-330 and 790-800.

325>327<330