Calculate the molarity of Fe(NO3)3 in Solution A.
Solution A: Mass of Fe(NO3)3 solid: 1.21g & Vol of Solution: 100mL
In a previous ? Using the mass I weighed 404.0g/mol to calculate moles of Fe(NO3)3 in solid hydrate----I got 0.00300 mol Fe(NO3)3)
Nvm haha all I had to do was divide it by the volume
glad you figured it out.
To calculate the molarity (M) of Fe(NO3)3 in Solution A, we need to first calculate the number of moles of Fe(NO3)3 in the solution.
Given:
Mass of Fe(NO3)3 solid = 1.21 g
Molar mass of Fe(NO3)3 = 404.0 g/mol
Volume of solution = 100 mL = 0.1 L
First, we need to find the moles of Fe(NO3)3 in the solid:
Moles of Fe(NO3)3 = Mass of Fe(NO3)3 / Molar mass of Fe(NO3)3
Moles of Fe(NO3)3 = 1.21 g / 404.0 g/mol
Moles of Fe(NO3)3 = 0.003 mol Fe(NO3)3
Now, we can calculate the molarity of Fe(NO3)3 in Solution A:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity (M) = 0.003 mol Fe(NO3)3 / 0.1 L
Molarity (M) = 0.03 M
Therefore, the molarity of Fe(NO3)3 in Solution A is 0.03 M.
To calculate the molarity of Fe(NO3)3 in Solution A, you need to use the formula:
Molarity (M) = Moles of solute / Volume of solution (in liters)
First, let's start by calculating the moles of Fe(NO3)3 in Solution A using the given mass and molar mass.
Given:
Mass of Fe(NO3)3 solid = 1.21g
Molar mass of Fe(NO3)3 = 404.0 g/mol
Moles of Fe(NO3)3 = Mass / Molar mass
Moles of Fe(NO3)3 = 1.21g / 404.0 g/mol = 0.00299 mol (rounded to four decimal places)
Now, we need to convert the volume of the solution from milliliters to liters:
Volume of Solution A = 100mL = 100 / 1000 = 0.100 L
Finally, we can calculate the molarity of Fe(NO3)3 in Solution A:
Molarity (M) = Moles / Volume
Molarity (M) = 0.00299 mol / 0.100 L = 0.0299 M (rounded to four decimal places)
Therefore, the molarity of Fe(NO3)3 in Solution A is 0.0299 M.