a 1 kg textbook has been pushed and let go sliding to the left on a flat table no one is pushing the book at this moment. it is sliding
a. calculate the weight of the textbook? How do I do these calculations?
b. based on this weight, what must the normal force from the table be on the book?
c. if the friction force is 5N in magnitude, what is the acceleration of the book?
d. is the book speeding up or slowing down? I said it is slowing down
a. weight = mass * g
b. normal force equals weight
... but in opposite direction
c. Newton's 2nd law ... f = m a
... in this case ... a = f / m
d. correct
a. To calculate the weight of an object, you need to multiply its mass by the acceleration due to gravity. The formula for weight is:
Weight = Mass x Acceleration due to Gravity
In this case, the mass of the textbook is given as 1 kg. The standard acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the textbook is:
Weight = 1 kg x 9.8 m/s^2
= 9.8 N
So, the weight of the textbook is 9.8 Newtons (N).
b. The normal force from the table on the book is equal in magnitude but opposite in direction to the weight of the book. Since we determined that the weight of the textbook is 9.8 N, the normal force from the table on the book must also be 9.8 N, but acting in the upward direction. This is because the normal force counteracts the force pushing the book down, which is its weight in this case.
c. To find the acceleration of the book, you need to consider the net force acting on it. In this scenario, the only horizontal force acting on the book is the friction force. The net force can be found using Newton's second law of motion:
Net Force = Mass x Acceleration
In this case, the mass of the textbook is 1 kg, and the friction force is given as 5 N. Therefore, the net force is:
Net Force = 5 N
Since the mass is 1 kg, we can rearrange the equation to solve for acceleration:
Acceleration = Net Force / Mass
= 5 N / 1 kg
= 5 m/s^2
So, the acceleration of the book is 5 m/s^2.
d. If the book is sliding to the left on a flat table and the friction force is acting to the right, the friction force is opposing the motion of the book. Since the friction force is greater than zero, and it is opposing the motion, the book is indeed slowing down.