Ricky can ride 17 km on his bike in the same length of time ha can walk 9 km.if his riding speed is 4 kph faster than his walking speed how fast does he walk
since time = distance/speed, if his walking speed is x km/hr,
9/x = 17/(x+4)
Now crank it out.
To find out Ricky's walking speed, let's first assume that his walking speed is 'x' km/h.
We are given that Ricky can ride 17 km in the same length of time he can walk 9 km. Since time is constant, we can set up the following equation:
Time taken to ride 17 km = Time taken to walk 9 km
To calculate time, we can divide distance by speed:
17 km / (walking speed) = 9 km / (riding speed)
Since we know that Ricky's riding speed is 4 km/h faster than his walking speed, we can substitute (x + 4) for his riding speed:
17 km / x = 9 km / (x + 4)
Next, we can cross-multiply to eliminate the fractions:
17(x + 4) = 9x
Expanding the equation:
17x + 68 = 9x
Simplifying the equation:
17x - 9x = -68
8x = -68
Dividing both sides by 8:
x = -68 / 8
x = -8.5
Therefore, Ricky's walking speed is -8.5 km/h. However, it is important to note that negative speeds don't make sense in this context. Therefore, we can conclude that Ricky's walking speed cannot be negative.
We can conclude that there is no valid walking speed for Ricky in this scenario, as a negative walking speed is not possible.