Rain drops fall on a tile surface at a density of 4380 drops/ft^2. There are 15 tiles/ft^2. How many drops fall on each tile? Answer in units of drops/tiles.

To find out how many drops fall on each tile, we need to divide the density of raindrops by the number of tiles per square foot.

Let's break down the problem:

Density of raindrops = 4380 drops/ft^2
Number of tiles per square foot = 15 tiles/ft^2

To find the number of drops per tile, we divide the density of raindrops by the number of tiles per square foot:

Number of drops per tile = Density of raindrops / Number of tiles per square foot

Substituting the given values:

Number of drops per tile = 4380 drops/ft^2 / 15 tiles/ft^2

When we divide one quantity by another, we can simplify it by multiplying the numerator by the reciprocal of the denominator:

Number of drops per tile = 4380 drops/ft^2 * 1/(15 tiles/ft^2)

Now, let's simplify the units:

Number of drops per tile = (4380 drops * ft^2) / (15 tiles * ft^2)

The ft^2 units will cancel out:

Number of drops per tile = 4380 drops / 15 tiles

So, the number of drops that fall on each tile is approximately 292 drops/tile.

4380/15=292

Answer: 292 drops/tile