What are the similarities between organized counting and permutation? Explain using examples.
I can only think of one similarity: they both use probability problems using counting P(event)= Number of favourable outcomes/Total number of possible outcomes.
Thanks for your help.
1. This tree diagram shows the number of theaters and the number of different movies being shown at theater. According to the diagram, how many possible movie choices are there?
A. 2
B.3
C.6
D.8
C.6
Which scenario is represented by this tree diagram?
A. 3 kinds of soup in 4 different sizes
B. 2 pairs of shoes and 5 colors of socks
C. 2 different CDs with 6 songs on each
D. 2 types of cake, in 2 different shapes, with 2 different types of frosting
D. 2 types of cake, in 2 different shapes, with 2 different types of frosting
. Find the total number of possible outcomes for 4 different cell phone models, each of which has 3
A. 7
B. 12
C. 16
D. 24
D. 24
There are 4 different cell phone models and each model has 3 different colors. So, the total number of possible outcomes is:
4 × 3 = 12
And since each phone model can have 2 different memory options:
12 × 2 = 24.
. Find the total number of possible outcomes for 10 styles of running shoes, each in a men's and women's version
A. 8
B. 12
C. 20
D. 100
C. 20
There are 10 styles of running shoes and each style has a men's and women's version. So, the total number of possible outcomes is:
10 × 2 = 20.
A pizza shop offers 12 different pizza toppings. If the total number of possible outcomes is 36, how many different sizes of single topping pizzas do they offer?
A. 2
B. 3
C. 6
D. 24
B. 3
The total number of possible outcomes is given as 36, which means there are 36 different ways to combine toppings on a pizza. We know that there are 12 different toppings, so we can assume that each pizza can have up to three toppings (because 12^3 = 1,728, which is more than 36).
So, the pizza shop offers three different sizes of single topping pizzas.