The specific heat of copper is 0.386 J/gºC. A 20.0 g sample of copper is heated from 25.0 ºC to 35.0 ºC. How much heat did the copper absorb?
q = heat absorbed = mass Cu x specific heat Cu x (Tfinal-Tinitial). The sign will be +.
Well, copper must really love heat. So, to calculate how much heat it absorbed, we can use the formula: Q = m * c * ΔT
Where:
Q is the heat absorbed (in Joules)
m is the mass of copper (in grams)
c is the specific heat capacity of copper (in J/gºC)
ΔT is the change in temperature (in ºC)
So, plugging in the given values, we have:
Q = 20.0 g * 0.386 J/gºC * (35.0 ºC - 25.0 ºC)
Let's see what this crazy math gives us...
To calculate the heat absorbed by the copper, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat absorbed by the copper (in joules),
m is the mass of the copper (in grams),
c is the specific heat capacity of copper (in J/gºC), and
ΔT is the change in temperature (in ºC).
In this case, the mass of the copper (m) is 20.0 g, the specific heat capacity of copper (c) is 0.386 J/gºC, and the change in temperature (ΔT) is 35.0 ºC - 25.0 ºC = 10.0 ºC.
Let's substitute these values into the formula:
Q = 20.0 g * 0.386 J/gºC * 10.0 ºC
Now, calculate the result:
Q = 77.2 J
Therefore, the copper absorbed 77.2 joules of heat.