lim x→0 of [tan(3x^2) + sin^2(5x)] / (x^2)

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  1. Hey, I did the other one, try series approach on this one too.

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  2. by the way tangent of small angle approaches sine of that small angle :) theta + theta^2/2 .......

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  3. recall that lim x->0 of sinx/x and tanx/x = 1

    You have

    tan(3x^2)/x^2 + sin^2(5x)/x^2
    = 3*tan(3x^2)/(3x^2) + 25(sin5x/5x)^2
    --> 3+25
    = 28

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