A ball rolls down a hill which has a vertical height of 15m .ignoring friction, what would be the (A)gravitation potential energy of the ball when it is at the top of the
hill?
(B)velocity of the ball when it reaches the bottom of the hill?
Ep =mgh h=15 g=9,8 v=o(15)(9,8)(0)=0
To calculate the gravitational potential energy at the top of the hill (A), we need to use the formula:
Gravitational Potential Energy (PE) = mass (m) x gravity (g) x height (h)
Since the problem does not provide the mass of the ball, we cannot calculate the exact value of the gravitational potential energy. However, we can still explain how to approach the problem. To find the gravitational potential energy, you need to know the mass of the ball. Once you know the mass, you can multiply it by the acceleration due to gravity (approximately 9.8 m/s^2) and the height of the hill to get the gravitational potential energy. In this case, the height of the hill is given as 15m.
To calculate the velocity of the ball when it reaches the bottom of the hill (B), we can use the principle of conservation of energy. The total mechanical energy (KE + PE) remains constant if there is no friction or external forces acting on the ball.
At the top of the hill, the ball will have gravitational potential energy (PE) and no kinetic energy (KE). When it reaches the bottom of the hill, it will have kinetic energy (KE) but no gravitational potential energy (PE). So, we can equate the initial potential energy (PE) to the final kinetic energy (KE):
PE = KE
Using the formula for gravitational potential energy, we can rewrite the equation as:
mgh = 0.5mv^2
Where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8 m/s^2), h is the height of the hill (15m), and v is the velocity of the ball.
From this equation, we can see that the mass of the ball cancels on both sides. Thus, the mass does not affect the velocity of the ball when it reaches the bottom of the hill. We are left with:
gh = 0.5v^2
To solve for v, we can rearrange the equation:
v = sqrt(2gh)
Substituting the values of g (9.8 m/s^2) and h (15m) into the equation, you can calculate the velocity of the ball when it reaches the bottom of the hill.
I need calculations
(A) m g h = 15 m g
(B) m g h = 1/2 m v^2
... v = √(2 g h) = √(30 g)