If XZ=50, what are XY and YZ
XY=a
YZ=a+8
Can someone help me ASAP..IM SO CONFUSED
xy+yz=xz
a+a+8=50
2a=42
a=21
a+8=29
Sure, I can help you with that.
We are given that XZ = 50.
We also have the information that XY = a and YZ = a + 8.
Now, since XZ is the sum of XY and YZ, we can set up the equation:
XY + YZ = XZ
Substituting the given values, we get:
a + (a + 8) = 50
Simplifying the equation:
2a + 8 = 50
Subtracting 8 from both sides:
2a = 50 - 8
2a = 42
Dividing both sides by 2:
a = 42/2
a = 21
So, XY = a = 21, and YZ = a + 8 = 21 + 8 = 29.
Therefore, XY = 21 and YZ = 29.
Of course, I can help you solve this problem.
Given that XZ = 50 and XY = a, we can find the value of a by subtracting YZ from XZ.
XZ = XY + YZ
50 = a + (a + 8) (substituting the given values: XY = a and YZ = a + 8)
Now we can solve for a:
50 = 2a + 8 (combining like terms)
42 = 2a (subtracting 8 from both sides)
a = 21 (dividing both sides by 2)
So, XY is equal to 21.
To find YZ, we can substitute the value of XY into the equation YZ = XY + 8:
YZ = 21 + 8
YZ = 29
Therefore, XY is 21 and YZ is 29.