This is a Quantitative Redox titration.
(KMnO4) = 1.8 G.. 500 ML
after the experiment we had to record the data of the 3 trials.
1. Trial - VolUme FeSO4 = 10.00 Ml - VOlume KMnO4 11.00 Ml
2. Trial - VolUme FeSO4 = 10.00 ML - VOlume KMnO4 11.15 Ml
and we ran outa the solution.. so we didn't have to do trial3
Question is Find the MOlarity of FeSO4 Solution.?
find the amount of feso4 and then calculae the molarity by using the formula!!!!
To find the molarity (M) of the FeSO4 solution, you can use the following equation:
M1V1 = M2V2
Where:
M1 = molarity of KMnO4 solution
V1 = volume of KMnO4 solution
M2 = molarity of FeSO4 solution
V2 = volume of FeSO4 solution
Given data:
M1 = molarity of KMnO4 = 1.8 g / 500 mL
V1 = volume of KMnO4 = 11.00 mL (for Trial 1) or 11.15 mL (for Trial 2)
Now, let's calculate the molarity of FeSO4 using Trial 1 and Trial 2 data separately:
For Trial 1:
M2 * 10.00 mL = 1.8 g / 500 mL * 11.00 mL
Simplifying the equation, we get:
M2 = (1.8 g / 500 mL * 11.00 mL) / 10.00 mL
Calculating this expression will give you the molarity of the FeSO4 solution for Trial 1.
Similarly, for Trial 2:
M2 * 10.00 mL = 1.8 g / 500 mL * 11.15 mL
Simplifying the equation, we get:
M2 = (1.8 g / 500 mL * 11.15 mL) / 10.00 mL
Calculating this expression will give you the molarity of the FeSO4 solution for Trial 2.
Since you do not have Trial 3 data, you cannot calculate the molarity based on that trial. However, you can take the average of the molarities calculated from Trial 1 and Trial 2 to approximate the molarity of the FeSO4 solution.